Directions (Q. 1–5): In each of these questions, two equations numbered I and II with variables x and y are given. You have to solve both the equations to find the value of x and y. Give answer
(a) if x > y
(b) if x >= y
(c) if x <y
(d) if x <= y
(e) if x = y or relationship between x and y cannot be determined.
Q1. I. 5x2 – 8x + 3 = 0
II. 3y2 + 5y – 2 = 0
Q2. I. x8 – (3 * 8)17/2/√x = 0
II. 11/√y + 18/√y = √y
Q3. I. √169 x2– 2197 = 0
II. √ (484) y + 132 = 0
Q4. I. (625)(1/4) x + √ (1225) = 155
II. 225y2 + 18 = 279
Q5. I. x2 – 7x + 12 = 0
II. y2 – 9y + 20 = 0
Directions(6-10): What value should come in the place of question mark (?) in the following number series?
Q6. 139, 175, 126, 190, 109, ?
(a) 219
(b) 209
(c) 201
(d) 212
(e) 203
Q7. 448, 225, 76, ?, 5
(a) 45
(b) 15
(c) 18
(d) 20
(e) 55
Q8. 342, ?, 396, 450, 522, 612
(a) 360
(b) 370
(c) 348
(d) 380
(e) 350
Q9. 219, 220, 247, 372, ?, 1444
(a) 615
(b) 715
(c) 815
(d) 425
(e) 625
Q10. 41, 85, 175, 357, 723, ?
(a) 1475
(b) 1437
(c) 1427
(d) 1587
(e) 1457
SOLUTIONS
1. (a)
I. 5x2 – 5x – 3x + 3 = 0
5x(x – 1) –3 (x – 1) = 0
x = 1, 3/5
II. 3y2 + 6y – y – 2 = 0
3y (y + 2) –1 (y + 2) = 0
(y + 2) (3y – 1) = 0
y = –2, 1/3
x > y
2. (c)
I. x17/2 = (24)17/2
x = 24
II. y = 29
y > x
3. (a)
I. 13x = 2197
x = 169
II. 22y = – 132
y = – 6
x > y
4. (a)
I. √ (25)x +35 = 155
x = 120/5 = 24
II. 15y = 261
y = 17.4
x > y
5. (d)
I. x2 – 4x – 3x + 12 = 0
(x – 4) (x – 3) = 0
x = 4, 3
II. y2 – 5y – 4y + 20 = 0
(y – 5) (y – 4) = 0
y = 5, 4
y >=x
9. (b)
The series is:
10. (e)
The series is:
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